Question

A new youth activity center is being built in oak valley. the perimeter of the rectangular playing field is 332 yards. the length of the field is 5 yards less than double the width. what are the dimensions of the playing​ field?

Answer 1

In this question, it is given that

A new youth activity center is being built in oak valley. the perimeter of the rectangular playing field is 332 yards. the length of the field is 5 yards less than double the width.

Let the width is x yards . And length is 5 yards less than double the width, so length is (2x-5) yards  .

Perimeter is the sum of all sides, that is

$x+2x-5+x+2x-5 = 332 \\ 6x-10 = 332 \\  6x = 342 \\ x = 57 yards  $

So the width is 57 yards and length is

$2x-5 = 2*57-5 = 109 yards$