Respuesta :
Let us assume that the weight of carrots is "X" kilogram
Since the total weight is 9 kilograms, the weight of potatoes should be "9-X" kilograms.
The cost of "X" kilograms of carrot at $0.75/kilogram is calculated as = 0.75*X = 0.75X
The cost of "9-X" kilograms of potatoes at $0.70/kilogram is calculated as 0.70*(9-X)
We know that the total cost is $6.60
We now frame the equation as:
0.75X + (9-X)*0.70 = 6.60
0.75X + 6.30 -0.70X = 6.60
0.05X = 0.30
X = 0.30/0.05 = 30/5 = 6
Therefore weight of carrots = 6 Kilograms and
Weight of potatoes = 9-6 = 3 Kilograms
Amount of Carrot bought at $0.75 per kilogram = x
Amount of potatoes bought at $0.70 per kilogram = y
Since, a shopper bought 9 kg of the vegetables.
Therefore, x + y =9 (equation 1)
A shopper bought 9 kg of vegetables at $6.60.
Therefore, 0.75x+0.70y=6.60
Multiplying the above equation by 100.
75x+70y=660 (equation 2)
Multiplying equation 1 by '-75' and adding it to the equation 2, we get
-75x-75y+75x+70y = 660-675
-5y = -15
y = 3
x + y = 9
x + 3 = 9
x = 9 - 3 = 6
Therefore, the shopper bought 6kg of carrots and 3 kg of potatoes.
