Evaluate 10m +\dfrac {n^2}410m+ 4 n 2 ​ 10, m, plus, start fraction, n, start superscript, 2, end superscript, divided by, 4, end fraction when m=5m=5m, equals, 5 and n=4n=4n, equals, 4.

Respuesta :

It was hard to read your question because that is not typed in proper format. Best that i can read your expression is :

[tex] 10m+\frac{n^2}{4} [/tex]

Now we have to evaluate it for given values m=5 and n=4

So let's plug these values into given expression.

[tex] 10m+\frac{n^2}{4} [/tex]

[tex] = 10(5)+\frac{4^2}{4} [/tex]

[tex] = 10(5)+\frac{16}{4} [/tex]

[tex] = 10(5)+4 [/tex]

[tex] = 50+4 [/tex]

[tex] = 54 [/tex]

Hence final answer is 54.

The value of the equation is given by substituting the value of m and n and taking LCM and adding the terms then simplifying the equation.

The solution of the equation is 54.

Given

Equation; [tex]\rm 10m+\dfrac{n^2}{4}[/tex]

How to calculate the value of the equation?

The value of the equation is given by substituting the value of m and n and taking LCM and adding the terms then simplifying the equation.

Substitute the value of m = 5 and n = 4 in the equation.

Therefore,

The value of the equation is;

[tex]\rm =10m+\dfrac{n^2}{4}\\\\= 10(5)+\dfrac{4^2}{4}\\\\= 50+\dfrac{16}{4}\\\\=50+4\\\\=54[/tex]

Hence, the value of the equation is 54.

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