Question

Give the equation of the circle centered at the origin and passing through the point -8 0

Answer 1

The equation of circle that passes through origin is given by

$x^2 + y^2 = r^2$

And the given circle passes through (-8,0).

Substituting -8 for x and 0 for y, we will get

$(-8)^2 + 0^2 = r^2 \\ 64=r^2 \\ r=8$

So the required equation of corcle is

$x^2 + y^2 =64$