Write a balanced equation for the complete combustion of 2,3-dimethylbutane. use the molecular formula for the alkane (c before h) and the smallest possible integer coefficients.

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2C_6H_14 + 19O_2 → 12CO_2 + 14H_2O

Step 1. Write the condensed structural  formula for 2,3-dimethylbutane.

(CH_3)_2CHCH(CH_3)_2

Step 2. Write the molecular formula.

C_6H_14

Step 3. Write the unbalanced chemical equation.

C_6H_14 + O_2 → CO_2 + H_2O

Step 4. Pick the most complicated-looking formula (C_6H_14) and balance its atoms (C and H).

1C_6H_14 + O_2 → 6CO_2 + 7H_2O

Step 5. Balance the remaining atoms (O).

1C_6H_14 + (19/2)O_2 → 6CO_2 + 7H_2O

Oops! Fractional coefficients!

Step 6. Multiply all coefficients by a number (2) to give integer coeficients..

2C_6H_14 + 19O_2 → 12CO_2 + 14H_2O

Answer:

The balanced chemical reaction is given as:

[tex]2C_6H_{14}+19O_2\rightarrow 12CO_2+14H_2O[/tex]

Explanation:

Combustion is a type of chemical reaction in which hydrocarbon reacts with oxygen gas to form carbon dioxide gas and water .

When 2,3-dimethylbutane undergoes combustion reaction it gives carbon dioxde and water.

The balanced chemical reaction is given as:

[tex]2C_6H_{14}+19O_2\rightarrow 12CO_2+14H_2O[/tex]

According to stoichiometry, 2 moles of 2,3-dimethylbutane reacts with 19 moles of oxygen gas to give 12 moles of carbon dioxide and 14 moles of water.

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