Respuesta :
2C_6H_14 + 19O_2 → 12CO_2 + 14H_2O
Step 1. Write the condensed structural formula for 2,3-dimethylbutane.
(CH_3)_2CHCH(CH_3)_2
Step 2. Write the molecular formula.
C_6H_14
Step 3. Write the unbalanced chemical equation.
C_6H_14 + O_2 → CO_2 + H_2O
Step 4. Pick the most complicated-looking formula (C_6H_14) and balance its atoms (C and H).
1C_6H_14 + O_2 → 6CO_2 + 7H_2O
Step 5. Balance the remaining atoms (O).
1C_6H_14 + (19/2)O_2 → 6CO_2 + 7H_2O
Oops! Fractional coefficients!
Step 6. Multiply all coefficients by a number (2) to give integer coeficients..
2C_6H_14 + 19O_2 → 12CO_2 + 14H_2O
Answer:
The balanced chemical reaction is given as:
[tex]2C_6H_{14}+19O_2\rightarrow 12CO_2+14H_2O[/tex]
Explanation:
Combustion is a type of chemical reaction in which hydrocarbon reacts with oxygen gas to form carbon dioxide gas and water .
When 2,3-dimethylbutane undergoes combustion reaction it gives carbon dioxde and water.
The balanced chemical reaction is given as:
[tex]2C_6H_{14}+19O_2\rightarrow 12CO_2+14H_2O[/tex]
According to stoichiometry, 2 moles of 2,3-dimethylbutane reacts with 19 moles of oxygen gas to give 12 moles of carbon dioxide and 14 moles of water.