Question

A sample of aluminum is placed in a 25-ml graduated cylinder containing 10.0 ml of water. the level of the water rises to 18.0 ml. aluminum has a density of 2.7 g/ml. calculate the mass of the sample.

Answer 1

Answer:

The mass of the aluminium sample is 21.6 grams.

Explanation:

Mass of the sample of aluminium = m

Volume of the aluminium = V

Density of the aluminum = d = 2.7 g/mL

Initial level of water mark in cylinder = 10.0 mL

Final level of water after sample is immersed = 18.0 mL

Volume occupied by the sample = V = 18.0 mL - 10.0 mL = 8.0 mL

$Density=\frac{Mass}{Volume}$

$Mass=Density\times Volume = d\times V$

$m=2.7 g/mL\times 8 mL= 21.6 g$

The mass of the aluminium sample is 21.6 grams.

Answer 2

The mass of the aluminum sample placed in the 25-mL graduated cylinder is 22 g.

A graduated cylinder contains 10.0 mL of water and after a piece of aluminum is added the volume increases to 18.0 mL. The volume of the piece of aluminum is equal to the differences in the registered volumes of water.

$V = 18.0 mL - 10.0 mL = 8.0 mL$

The piece of aluminum has a volume of 8.0 mL and its density is 2.7 g/mL. The mass of this piece is:

$8.0 mL \times \frac{2.7g}{mL} = 22 g$

The mass of the aluminum sample placed in the 25-mL graduated cylinder is 22 g.

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