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28-08-2018
Mathematics

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Find the length of x for the right triangle

Find the length of x for the right triangle class=

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29-08-2018

[tex] \sin\theta=\dfrac{opposite}{hypotenuse}\\\\opposite=x\\hypotenuse=7\\\theta=34^o\to\sin37^o\approx0.6018\\\\\text{substitute}\\\\0.6018=\dfrac{x}{7}\ \ \ \ |\cdot7\\\\x=4.2126\\\\x\approx4.21 [/tex]

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