Question

the length of one base of a trapezoid is 19 less than five times the length of the other base. If the trapizoid has a height of 18 feet and an area of 477ft to the 2nd square, fing the length of the longer base

Answer 1

Let the length of one base of trapezoid be x, and the length of other base is 19 less than 5 times the length .

So the other base is

$5x-19$

And the formula of area of trapezoid is

$A = ( \frac{b_{1} + b_{2}}{2}) *h$

$477 = ( \frac{x+5x-19}{2} )*18$

Dividing both sides by 18,

$ 26.5= \frac{6x-19}{2} \\ 53 = 6x-19 \\ 72 = 6x \\ x = 12$

So length of the longer base is

$= 5(12)-19 = 41$