Question

Find two consecutive numbers whose sum is 115

Answer 1

Let's call the first number x. We know that the second number is consecutive (which means it comes right after the first number), so it's going to be x + 1.

We know when you work out the sum of these two numbers, it equals 115, so now you can form an expression:

x + (x + 1) = 115

Now you just need to simplify and combine the similar terms:

2x + 1 = 115

Now subtract 1 from both sides:

2x = 114

And finally, divide by 2 on both sides to isolate the x:

x = 57

Now that you know x = 57 (where x is the first number), you know that the second number is going to be 1 more than that (as it's consecutive). So it's going to 58.

Your two numbers are 57 and 58. And when you add them together, you'll get 115 (as 57 + 58 = 115).

Answer 2

Consecutive numbers are numbers that have a difference of 1. The consecutive number whose sum is 115 are 57 and 58.

Let the numbers be x and y;

Such that:

$y - x = 1$

Make y the subject

$y = x + 1$

So, we have:

$Sum = x + y$

This gives:

$x + y = 115$

Substitute $y = x + 1$

$x + x + 1 = 115$

$2x + 1 = 115$

Collect like terms

$2x = 115 - 1$

$2x = 114$

Divide both sides by 2

$x = 57$

Recall that:

$y = x + 1$

$y = 57+1$

$y = 58$

Hence, the numbers are 57 and 58

Read more about consecutive numbers at:

https://brainly.com/question/2493629