Question

Find the first three terms of the sequence defined by an = 4n − 2 (separated by a comma).

Answer 1

we have

$an = 4n- 2$ -------> equation $1$

Find the first term of the sequence

For $n=1$

substitute the value of n in the equation $1$

$a(1) = 4*1- 2$

$a(1) = 2$

Find the second term of the sequence

For $n=2$

substitute the value of n in the equation $1$

$a(2) = 4*2- 2$

$a(2) = 6$

Find the third term of the sequence

For $n=3$

substitute the value of n in the equation $1$

$a(3) = 4*3- 2$

$a(3) = 10$

therefore

the answer is

The first three terms of the sequence is $[2,6,10]$