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For the given equation, we use slope intercept form, which is

[tex] y = mx +b [/tex]

Where y is the height, m is the rate and b is the initial height.

Substituting the given values, we will get

[tex] y = -850x + 30000 [/tex]

Part b

Here we put x=8

[tex] y= -850(8)+30000 = 23200feet [/tex]

A plane was flying at an altitude of 30,000 feet when it began its descent toward the airport. The plane descends at a rate of 850 feet per minute.

Write a function rule that describes this situation

Answer: Let S be the altitude (in feet).

We know that plane's altitude is decreasing at the of 850 feet per minute from the initial altitude 30,000 feet.

[tex] S=30,000-850 \times t [/tex]

Where t is the time in minutes

b) What is the altitude of the plane after it has descended for 8 min?

Answer: After 8 minutes plane's altitude is

[tex] S=30,000-850 \times 8 [/tex]

          =[tex] 30,000-6800 [/tex]

          [tex] =23200 [/tex] feet

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