Respuesta :
27.6g to 3 sig fig. Moles ratio of CO: H2 is 8:17 so if there is 6.50 moles of CO reacting it is with (17/8 x 6.5) = 13.81 moles of H2. The Mr of H2 is 2x1 = 2. The mass of H2 = moles x Mr so 13.81 x 2 = 27.6
Answer:
Mass of H2 = 27.6 g
Explanation:
Given:
Moles of CO = 6.50
The balanced reaction is:
8CO + 17H2 → C8H18 + 8H2O
Based on the reaction stoichiometry:
8 moles of CO reacts with 17 moles of H2
Therefore, 6.50 moles of CO would react with:
= [tex]\frac{6.50\ moles\ CO * 17\ moles\ H2}{8\ moles\ CO} = 13.8 moles[/tex]
Molar mass of H2 = 2 g/mole
Mass of H2 reacted = [tex]Moles *molar mass = 13.8 moles * 2g/mol= 27.6 g[/tex]
