what is the length of AC in the given triangle

We know: The sum of measures of the angles in a triangle is equal 180°.
[tex]m\anlge A=180^o-(85^o+53^o)=42^o[/tex]
Use Law of sines:
[tex] \dfrac{b}{\sin85^o}=\dfrac{85}{\sin42^o}\\\\\dfrac{b}{0.9962}=\dfrac{85}{0.6691}\ \ \ \ |\text{cross multiply}\\\\0.6691b=85\cdot0.9962\\\\0.6691b=84.677\ \ \ \ |:0.6691\\\\b\approx126.5536\\\\\text{Answer:}\ 126.6 [/tex]