Respuesta :
the question is English is
Part a) The square of a number minus 5 equals 220. What is that number?
Part b) The square of a number plus the same number equals 306. What is that number?
Part a) The square of a number minus 5 equals 220. What is that number?
Let
x--------> the number
we know that
[tex]x^{2} -5= 220 \\ \\ x^{2}= 220+5 \\\\x^{2} =225 \\\\x=\sqrt{225} \\ \\x=15[/tex]
therefore
the answer Part 1) is
the number is 15
Part 2) The square of a number plus the same number equals 306. What is that number?
Let
x--------> the number
we know that
[tex]x^{2} +x= 306[/tex]
using a graph tool------> to resolve the second order equation
see the attached figure
the solution are
x=-18
x=17
Check
for x=-18
[tex](-18)^{2} +(-18)= 306 \\ 306=306[/tex]
for x=17
[tex](17)^{2} +(17)= 306 \\ 306=306[/tex]
therefore
the answer Part 2) is
the numbers are -18 and 17
The answer in Spanish
Parte a)
Hagamos
x--------> el numero
Sabemos que
[tex]x^{2} -5= 220 \\ \\ x^{2}= 220+5 \\\\x^{2} =225 \\\\x=\sqrt{225} \\ \\x=15[/tex]
por lo tanto
La respuesta de la parte 1) es
El numero es 15
Parte 2)
Hagamos
x--------> El numero
Sabemos que
[tex]x^{2} +x= 306[/tex]
Usamos una herramienta grafica------> para resolver la ecuacion cuadratica
Ver la imagen adjunta
Las soluciones son
x=-18
x=17
Chequeamos
para x=-18
[tex](-18)^{2} +(-18)= 306 \\ 306=306[/tex]
para x=17
[tex](17)^{2} +(17)= 306 \\ 306=306[/tex]
por lo tanto
La respuesta de la parte 2) es
Los numeros son -18 and 17

Answer: Im translating this to english, hope this is not a problem for you :)
"El cuadrado de un número menos 5 es igual a 220. ¿Cuál es ese número?"
This says that a number square subtracted by 5 is equal to 220:
n^2 - 5 = 220
now we need to isolate n:
n^2 = 225
n = √225 = 15
then our number is 15.
"El cuadrado de un número mas el mismo número es igual a 306. ¿Cuál es ese número?"
The sum betwen a squared number and the same number is equal to 306, and we want to find this number:
n^2 + n = 306
this is a cuadratic equation, here we can use Bhaskara:
n^2 + n - 306 = 0
if we have a equation of the form:
[tex]ax^{2} + bx + c = 0[/tex]
the solutions are:
[tex]x = \frac{-b +/- \sqrt{b^{2} -4ac } }{2a}[/tex]
in this case; a = 1, b= 1 and c = 306, we can replace this in the equation and get:
[tex]n = \frac{ -1 +/- \sqrt{1 +4*1*306} }{2} = \frac{-1 +/-\sqrt{1225} }{2} = \frac{1 +/- 35}{2}[/tex]
So we have two solutions here; n = -36/2 = - 18 and n = 34/2 = 17