Respuesta :
Since both machines maintain their rate, the number of copies made and the elapsed time are proportional. This means that we can write a proportion like
[tex] \text{time}_1 : \text{copies in time}_1 = \text{time}_2 : \text{copies in time}_2 [/tex]
We know the performance of machine a for 12 minutes, and we want those for 30 minutes: the proportion becomes
[tex] 12 : 100 = 30 : x \iff x = \dfrac{100\cdot 30}{12} = \dfrac{3000}{12} = 250 [/tex]
Similarly, we have for machine b
[tex] 10 : 150 = 30 : x \iff x = \dfrac{150\cdot 30}{10} = \dfrac{4500}{10} = 450 [/tex]
So, together, the two machines make
[tex] 250+450 = 700 [/tex]
copies.
Rate at which machine a makes copies = 100/12 = 8 1/3 copies / minute
For machine b this rate is 150/10 = 15 copies/minute
So in 30 minutes they both make 30 * 15 + 30 * 8 1/3
= 700 answer