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I didnt do sig figs though perhaps you could do that ypurself
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Answer : The mass of sodium chloride obtained are 5.926 grams.

Explanation : Given,

Volume of solution = 350 mL

Molarity of sodium chloride = 0.287 M

Molar mass of sodium chloride (NaCl) = 59 g/mole

Molarity : It is defined as the number of moles of solute present in 1 liter of solution.

Formula used :

[tex]\text{Molarity}=\frac{\text{Mass of sodium chloride}\times 1000}{\text{Molar mass of sodium chloride}\times \text{Volume of solution (in mL)}}[/tex]

Now put all the given values in this formula, we get:

[tex]0.287M=\frac{\text{Mass of sodium chloride}\times 1000}{59g/mole\times 350mL}[/tex]

[tex]\text{Mass of sodium chloride}=5.926g[/tex]

Therefore, the mass of sodium chloride obtained are 5.926 grams.

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