Question

A 2in. piece of chocolate cake with frosting provides 1670 kj of energy. what is this in dietary calories(cal)

Answer 1

Answer:

399.1 dietary calories

Explanation:

A 2in. piece of chocolate cake with frosting provides 1670 kJ (1670 × 10³ J) of energy. We can express this in calories, knowing that 1 cal = 4.184 J.

1670 × 10³ J × (1 cal/4.184 J) = 3.991 × 10⁵ cal

The dietary calorie is an energy unit commonly used to describe the energy content of foods and 1 dietary calorie = 1 kcal = 10³ cal. The energy in dietary calories corresponding to 3.991 × 10⁵ calories is:

3.991 × 10⁵ cal × (1 dietary calory/ 10³ cal) = 399.1 dietary calory

Answer 2

The dietary calories in 1670 kilojoule of energy is 399.14 Cal

Given the data in the question;

Energy provided by the chocolate; $E = 1670kJ$

Energy in dietary calories(cal) = ?

We know that;

• There are 1000 cal per every calories C

• There are 4.184J per every calories cal

• There are 1000J per every kJ

Now we convert kilojoules(kJ) to dietary calories(cal)

Calories in 1670 kilojoules = $1670kJ * \frac{1000\ J}{1\ kJ} * \frac{1\ cal}{4.184\ J} * \frac{1\ Cal}{1000\ cal}$

Calories in 1670 kilojoules  = $399.14\ Cal$

Therefore, the dietary calories in 1670 kilojoule of energy is 399.14 Cal

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