To solve the problem, we must use the following equation:
[tex] Q=mC_s (T_f -T_i) [/tex]
where
Q is the amount of heat energy absorbed by the water
m is the mass of the water
Ti and Tf are the initial and final temperature
Cs is the specific heat capacity of the water
The data we have in this problem are:
Q=40.0 kJ
[tex] C_s =4.186 kJ/kg^{\circ}C [/tex]
[tex] T_i=10^{\circ}C [/tex]
m=0.500 kg
Substituting the data into the equation and re-arranging it, we find
[tex] T_f = T_i + \frac{Q}{mC_s}=10^{\circ}+\frac{40.0 kJ}{(0.500 kg)(4.186 kJ/kg^{\circ}}=29.1^{\circ}C [/tex]
So the final temperature of the water will be 29.1 degrees.
