For an object`s motion, the Kinematic equation is,
[tex] v^2=v_{0}^2+2ah [/tex]
Here, v is the final velocity and h is stands for the height of the object and a is the acceleration of the object.
As according to question,
[tex] v=0m/s,a=g-9.8 m/s^2 [/tex] and [tex] h = 0.400 m [/tex]
Thus, putting these values in above equation, we get
[tex] 0= v_{0}^2 -2gh [/tex]
or
[tex] v_{0} =\sqrt{2 \times 9.8 \times 0.400 } [/tex]
[tex] v_{0} = 2.8 m/s [/tex]
Therefore, initial velocity is 2.8 m/s