Respuesta :

For an object`s motion, the Kinematic equation is,

[tex] v^2=v_{0}^2+2ah   [/tex]

Here, v is the final velocity and h is stands for the height of the object and a is the acceleration of the object.

As according to question,

[tex] v=0m/s,a=g-9.8 m/s^2 [/tex] and [tex] h = 0.400 m [/tex]

Thus, putting these values in above equation, we get

[tex] 0= v_{0}^2 -2gh [/tex]

or

[tex] v_{0} =\sqrt{2 \times 9.8 \times 0.400 }   [/tex]

[tex] v_{0} = 2.8 m/s [/tex]

Therefore, initial velocity is 2.8 m/s



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