Answer: [tex] 5.06\times10^{9} [/tex]
At sea level, there is one standard atmospheric pressure which is equal to 101.325 kilopascals.
The pressure of faintest sound that a human ear can hear is 20 micro-pascals.
taking the ratio of two:
[tex] \frac {101.325 kilopascals. }{20 micropascals} = \frac {101.325 \times 10^{3}Pa}{20 \times 10^{-6}Pa} [/tex]
[tex] =5.06\times10^{9} [/tex]
Hence, the atmospheric pressure at sea level is [tex] 5.06\times10^{9} [/tex] times greater than the faintest sound that a human ear can hear.