Respuesta :

gmany

[tex] \dfrac{-10v+2}{5z+6}=-2\ \ \ \ |\cdot(5z+6)\neq0\\\\-10v+2=-2(5z+6)\\\\-10v+2=-10z-12\ \ \ \ |+12\\\\-10v+14=-10z\ \ \ \ |:(-10)\\\\z=v-1.4 [/tex]

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