Respuesta :

2[tex] e^{3x} [/tex] = 4[tex] e^{5x} [/tex]

[tex] e^{3x} [/tex] = 2[tex] e^{5x} [/tex] divided both sides by 2

ln ([tex] e^{3x} [/tex] ) = ln (2[tex] e^{5x} [/tex] ) applied "ln" to both sides

ln ([tex] e^{3x} [/tex] ) = ln 2 + ln tex] e^{5x} [/tex] ) applied the log product rule

3x = ln 2 + 5x applied "ln e = 1"

-2x = ln 2 subtracted 5x from both sides

x = [tex] \frac{ln2}{-2} [/tex] divided both sides by "-2"


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