Respuesta :
For this, I will be using the elimination method. So with this, subtract the second equation from the first equation to get [tex] 7x=-42 [/tex] . From here you can solve for x.
For this equation, just divide both sides by 7, and your first answer is [tex] x=-6 [/tex]
Now that we have the value of x, substitute it into either equation to solve for y:
[tex] -3(-6)-7y=-66\\ 18-7y=-66\\ -7y=-84\\ y=12\\ \\ -10(-6)-7y=-24\\ 60-7y=-24\\ -7y=-84\\ y=12 [/tex]
In short, x = -6 and y = 12.
Given system of equations:
[tex] \left \{ {{-3x~-~7y~=~-66} \atop {-10x~-~7y~=~-24}} \right. [/tex]
- Let's solve this system of equations using the substitution method. Solve for y in the first equation.
-3x - 7y = -66
- Add 3x to both sides.
-7y = -66 + 3x
- Divide both sides by -7.
y = 66/7 - 3/7x
- Plug y into the second equation.
-10x - 7(66/7 - 3/7x) = -24
- Distribute 7 inside the parentheses.
-10x - 66 + 3x = -24
- Combine like terms on the left side of the equation.
-7x - 66 = -24
- Add 66 to both sides.
-7x = 42
- Divide both sides by -7.
x = -6
- Plug -6 for x into the first equation.
-3(-6) - 7y = -66
- Multiply -3 * -6.
18 - 7y = -66
- Subtract 18 from both sides.
-7y = -84
- Divide both sides by -7.
y = 12
Your answer is:
- x = -6
- y = 12