We are given
amount $11,000 to invest
so,
P=11000
For Compounded continuously:
P=11000
r=0.0625
t=10
now, we can use formula
[tex]A=Pe^{rt}[/tex]
now, we can plug values
and we get
[tex]A=11000e^{0.0625*10}[/tex]
we get
[tex]A=20550.70553[/tex]
Amount is $ 20550.70553
For Compounded semi-annually:
P=11000
r=0.063
t=10
n=2
now, we can use formula
[tex]A=P(1+\frac{r}{n} )^{n*t}[/tex]
now, we can plug values
and we get
[tex]A=11000(1+\frac{0.063}{2} )^{2*10}[/tex]
now, we can simplify it
[tex]A=20453.95666 [/tex]
so, Amount is $20453.95666
so, amount for compounded continuously is greater...........Answer