Question

The length of a rectangle is 9 inches more than the width. The perimeter is 50 inches. Find the length and the width of the rectangle.

Answer 1

$w + w + (w + 9) + (w + 9) = 50$
$4w + 18 = 50$
$4w = 32$
$4w \div 4 = 32 \div 4$
$w = 8$
$l = 17$