Respuesta :
parallel lines, have the same exact slope, hmmm what is the slope of y = -2/3 x + 1/3 anyway? well, low and behold, the equation is already in slope-intercept form, therefore
[tex] \bf ~~y=\stackrel{slope}{-\cfrac{2}{3}}x+\cfrac{1}{3}~~ [/tex] has a slope of -2/3.
so we're really looking for a line whose slope is -2/3 and runs through 9,4.
[tex] \bf (\stackrel{x_1}{9}~,~\stackrel{y_1}{4})~\hspace{10em}slope = m\implies -\cfrac{2}{3}\\\\\\\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-4=-\cfrac{2}{3}(x-9)\\\\\\y-4=-\cfrac{2}{3}x+6\implies y=-\cfrac{2}{3}x+10 [/tex]
Hello!
If we want a parallel line, it needs to have the same slope as the other line. If we look at our first equation, the slope of the line is -2/3. This gives us y=-2/3x+b
To finish our equation, we will want to find b. To do so, we can plug the point (9,4) in for (x,y) and solve for b.
4=-2/3(9)+b
4=-6+b
b=10
This gives us our equation below.
y= -2/3x+10
I hope this helps!