Respuesta :

First of all, move all terms to the same side:

[tex] x^3 + 3x^2 - 8 x = 0 [/tex]

You can factor an x, which means that [tex] x = 0[/tex] is a solution:

[tex] x(x^2+3x-8) [/tex]

This expression is further factorizable if the quadratic equation has any solution. Using the quadratic formula, we can find that they are

[tex] x_{1,2} = -\dfrac{3 \pm \sqrt{41}}{2}[/tex]

So, we have

[tex] x(x^2+3x+8) = 0 = \iff x = 0,\quad x =-\dfrac{3 + \sqrt{41}}{2} ,\quad x =-\dfrac{3 - \sqrt{41}}{2}[/tex]

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