[tex] \bf P(\stackrel{\stackrel{x}{adjacent}}{15},\stackrel{\stackrel{y}{opposite}}{-8})\impliedby \textit{let's find the \underline{hypotenuse}}
\\\\\\
\textit{using the pythagorean theorem}
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c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}
\qquad
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
c=\sqrt{15^2+(-8)^2}\implies c=\sqrt{289}\implies c=17
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\rule{34em}{0.25pt}\\\\
~\hfill sin(\theta )=\cfrac{\stackrel{opposite}{-8}}{\stackrel{hypotenuse}{17}}\hfill [/tex]
