Question

three consecutive odd integers have a sum of 39. find x, the smallest of the three integers

Answer 1

The three integers are 11, 13, and 15.

Explanation:

We shall consider the integers as x, (x+2), and (x+4). The sum of these is 39, so we can write:

x+(x+2)+(x+4)=39

Open the brackets and simplify.

x+x+2+x+4=39

3x+6=39

Subtract 6 from each side.

3x=33

Divide both sides by 3.

x=11

Therefore: (x+2)=13 and (x+4)=15

hope this helps!

Answer 2

This may help you
(x) , (x+1) , (x+2)
Adding them
(X)+(x+1)+(x+2) = 39
3x+3=39
3x=36
So x+1 = 13.x+2= 14
I hope this help