Question

need help with number 10

Answer 1

We have a right triangle, where b is an opposite leg to angle B,

and c is hypotenuse.

So, we can write

$sin\ angle=\frac{opposite\ leg}{hypotenuse} \\ \\sin\ B=\frac{b}{c} \\ \\sin(25^{o})=\frac{b}{11} \\ \\b = 11*sin(25^{o}) \\ \\ b= 4.65$