We have a right triangle, where b is an opposite leg to angle B,
and c is hypotenuse.
So, we can write
[tex] sin\ angle=\frac{opposite\ leg}{hypotenuse}
\\ \\sin\ B=\frac{b}{c}
\\ \\sin(25^{o})=\frac{b}{11}
\\ \\b = 11*sin(25^{o})
\\ \\ b= 4.65 [/tex]
