Question

A certain restaurant offers 8 different salads, 5 different main courses, 6 different desserts. if customers choose one salad, one main course and two different desserts for their meal, how many different meals are possible?

Answer 1

$8\cdot5\cdot C(6,2)=40\cdot\dfrac{6!}{2!3!}=40\cdot\dfrac{4\cdot5\cdot6}{2}=2,400$