Question

Two pedestrians simultaneously left two villages 27 km apart and walked toward each other. the first one walked 4 km per hour, and the second walked 6 km per hour. after how many hours did the pedestrians meet?

Answer 1

Step 1: Assign variable for the unknown that you need to find.

Let ' t ' be the number of hours it took for the pedestrians to meet.

Step 2: List the give details

Speed of first pedestrian = 4 km/hr.

Speed of second pedestrian = 6 km/hr.

Distance between two pedestrians = 27 km.

Step 3: Set up an equation

The relationship between speed, distance and time is given below:

$Distance= \; Rate \times Time$

The first one walked 4 km per hour, distance traveled by first pedestrian is given below:

$Distance_{1^{st} \; pedestrian} \; = \; 4t\\\\Distance_{2^{nd} \; pedestrian} \; = \; 6t$

Two pedestrians simultaneously left two villages 27 km apart and walked toward each other.

$Distance_{1^{st} \; pedestrian} +Distance_{2^{nd} \; pedestrian} =27\\\\4t+6t=27\\Combine \; Like \; Terms\\\\10t=27\\Dividing \; 10 \; on \; both \; sides\\\\ \frac{10t}{10}  = \frac{27}{10}  \\Simplifying \; fraction \; on \; both \; sides\\\\t=2.7 \; hours$

Conclusion:

The pedestrian meet after 2.7 hours.