Question

what is the instantaneous acceleration at t=0?


0.6 m/s^2
1.67 m/s ^2
4.6 m/s ^2
6.27 m/s^2

Answer 1

I have the same physics class , so the answer would be 0.6

Answer 2

Answer:

0.6 m/sec^2

Explanation:

from the graph we find out the equation of line which will be a function of time and velocity. And differentiating that  we can find acceleration at t=0

two point in in graph are  (0,4) and (10,10)

therefore slope of the graph = 6/10= 3/5

we can find the equation of  line using one point form

$v-v_1= m(t-t_1)$

putting values we get

$v-4= 3/5(t-0)$

⇒5v-3t=20

differentiating we get

$5\frac{\mathrm{dv} }{\mathrm{d} t}-3=20$

$\frac{\mathrm{d} v}{\mathrm{d} t}=a=0.6$

hence the acceleration = 0.6 m/sec^2