Take your original equation [tex] \frac{x}{y} +\frac{y}{x} =-1 [/tex]
and multiply both sides by [tex] xy [/tex] to remove the fractions. You are left with
[tex] x^2+y^2=-xy [/tex]
So, [tex] x^2+y^2=-xy [/tex]
Update: There is no numerical answer that can be found without being given a value for either x or y
[tex] \dfrac{x}{y}+\dfrac{y}{x}=-1|\cdot xy\\\\
x^2+y^2=-xy\\\\
x^2+xy+y^2=0\\\\
\boxed{x^3-y^3=(x+y)(x^2+xy+y^2)}\\
\Downarrow\\
x^3-y^3=(x+y)\cdot 0\\\\
\boxed{\boxed{x^3-y^3=0}}
[/tex]