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  • 16-08-2018
  • Mathematics
contestada

Evaluate 3x+4(y+3) when x is 5 less than the quotient of y and 3, and y=18.

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Riia
Riia Riia
  • 16-08-2018

It is given that x is 5 less than the quotient of y and 3.

And given value of y is 18 .

So quotient of y and 3 is

[tex] \frac{18}{3} = 6 [/tex]

And 5 less than 6 =1

So we have y=18 and x=1

Given expression is

[tex] 3x+4(y+3) [/tex]

At x=1 and y=18, we will get

[tex] 3(1)+4(18+3) =3 + 4(21) [/tex]

[tex] = 3+84=87 [/tex]

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