We are given
system of equations as
[tex] 2x+3y=9 [/tex]
[tex] (a+b)x + (2a-b)y=3(a+b+1) [/tex]
It will have infinite solution when both equations will become same
so, we will set coefficients of x and y of both terms equal
We can see
coefficient of x in first equation is 2
coefficient of x in second equation is a+b
so, we get
[tex] a+b=2 [/tex]
coefficient of y in first equation is 3
coefficient of y in second equation is 2a-b
so, we get
[tex] 2a-b=3 [/tex]
now, we can find b from first equation
[tex] a+b=2 [/tex]
[tex] b=2-a [/tex]
we can plug it in above equation
[tex] 2a-(2-a)=3 [/tex]
now, we can solve for a
we get
[tex] a=\frac{5}{3} [/tex]
now, we can find b
[tex] b=2-\frac{5}{3} [/tex]
[tex] b=\frac{1}{3} [/tex]
so,
[tex] a=\frac{5}{3} [/tex]
[tex] b=\frac{1}{3} [/tex].................Answer