Question

A model rocket is launched at an angle of 70° above the x axis, with an initial velocity of 40 m/s. How high will the rocket be 5 seconds after launch?
A. 36.8 m
B. 65.4 m
C. 84.9 m
D. 122.5 m

Answer 1

Option (B) is correct.

using kinematic equation

$h= V sin\theta t+ \frac{1}{2}gt^2$

h= height of rocket

V= initial velocity= 40 m/s

t= time= 5 s

g= -9.8 m/s²

h=40 sin70 (5)+1/2 (-9.8)(5)²

h=65.4 m

Answer 2

Answer:

65.4 is your answer

Explanation: