Given exponential function
f(x)= [tex] 230 (0.881)^x [/tex]
Where x is the number of years
f(x) is the number of tuna in thousands
To find out when number of tuna is 50 thousand , we plug in 50 for f(x) and solve for x
[tex] 50 = 230(0.881)^x [/tex]
Divide by 230 on both sides
[tex] \frac{5}{23} = (0.881)^x [/tex]
Take ln on both sides
[tex] ln(\frac{5}{23}) = ln(0.881)^x [/tex]
[tex] ln(\frac{5}{23}) = x ln(0.881) [/tex]
Divide by ln(0.881) on both sides
x = [tex] \frac{ln(\frac{5}{23})}{ln(0.881)} [/tex]
x= 12.04
Year = 1974 + 12.04 = 1986
so in 1986 there will be 50 thousand tuna.