[tex] A=0.25^2+2*0.25\sqrt{\frac{0.25^2}{4}+ 1.2^2}
[/tex]Alright, lets get started.
The side of square base is given 0.25 in. (say a)
The height of pyramid is given 1.2 in. (say h)
The formula for surface area A is given below:
A=a^2+2a √(a^2/4+ h^2 )
Putting the value of a and h .
[tex] A=a^2+2a\sqrt{\frac{a^2}{4}+ h^2} [/tex]
Putting the value of a and h
[tex] A=0.25^2+2*0.25\sqrt{\frac{0.25^2}{4}+ 1.2^2}
A=0.0625+ 0.5\sqrt{\frac{0.0625}{4}+ 1.44}
A=0.0625+ 0.5\sqrt{0.015625 + 1.44}
A=0.0625+ 0.5\sqrt{1.455}
A=0.0625+ 0.5*1.20
A=0.0625+ 0.60
A = 0.6625 square inches [/tex]
Hence the area of pyramid is 0.6625 square inches. : Hope it will help :)
