Respuesta :
since we know the diameter of the cone is 6 inches, then its radius must be half that, namely 3 inches.
[tex] \bf \textit{volume of a cone}\\\\
V=\cfrac{\pi r^2 h}{3}~~
\begin{cases}
r=radius\\
h=height\\
-----\\
r=3\\
h=7
\end{cases}\implies V=\cfrac{\pi (3)^2(7)}{3}\implies V=21\pi [/tex]
we are given
diameter=6inches
we know that
diameter=2*radius
so, we get
radius=r=3inch
height=h=7inch
now, we can use cone volume formula
[tex] V=\frac{1}{3} \pi r^2h [/tex]
we can plug r and h
and we get
[tex] V=\frac{1}{3} \pi (3)^2(7) [/tex]
[tex] Volume= 65.97345 inch^3[/tex]..............Answer