suitcase can be pushed to a distance of 0.35 m
Explanation:
Work done= Ff d
w= 670 J
Ff= force of friction
d= distance
force of friction is given by Ff=μ mg
μ= coefficient of friction=2.76
m=mass=71.5 kg
so Ff= (2.76) (71.5) (9.8)
Ff=1934 N
so W= Ff d
670= 1934 d
d=0.35 m