Question

Potter's wheel rotating at 300 rev/min is switched off and rotates through 88.0 revolutions prior to coming to rest. what is the constant angular acceleration of the potter's wheel g

Answer 1

initial angular speed of the wheel is given by

$w_0 = 300 rev/min$

$w_0 = 2\pi * \frac{300}{60}$

$w_0 = 31.4 rad/s$

angular displacement of wheel till it stops

$\theta = 2 \pi N = 2\pi * 88$

$\theta = 552.92 rad$

now by the kinematics equations we will have

$w^2 - w_0^2 = 2\alpha \theta$

$0 - 31.4^2 = 2*\alpha * 552.92$

$\alpha = -0.89 rad/s^2$