Respuesta :
Energy of single uv photon= 7.95 x 10⁻¹⁸ J
Energy of a mole of photons=4788213 J
Explanation:
the energy of a photon is given by [tex] E= \frac{h c}{\lambda} [/tex]
h= planck's constant=6.626 x 10⁻³⁴ Js
λ= wavelength=25 nm= 25 x 10⁻⁹ m
c= velocity of light= 3 x 10⁸ m/s
so [tex] E= \frac{6.626\times10^{-34}(3\times10^{8})}{25\times10^{-9}} [/tex]
E=7.95 x 10⁻¹⁸ J
so energy of one photon=7.95 x 10⁻¹⁸ J
Energy of one mole of photons= 6.022 x 10²³ (7.95 x 10⁻¹⁸ J)
Energy of one mole of photons=4788213 J
The energy of one mole of photon is [tex]4.78 \times 10^{6} \;\rm J[/tex].
Given data:
The wavelength of photon is, [tex]\lambda = 25 \;\rm nm = 25\times 10^{-9} \;\rm m[/tex].
The energy of one photon is given as,
[tex]E=\dfrac{hc}{\lambda}[/tex]
Here, h is the Planck's constant and c is the speed of light.
Solving as,
[tex]E=\dfrac{6.63\times10^{-34} \times 3 \times 10^{8}}{25 \times 10^{-9}}\\E=7.956 \times 10^{-18} \;\rm J[/tex]
Now, energy of mole of photon is,
[tex]E'=N \times E[/tex]
N is the Avogadro's number.
[tex]E'=6.022 \times 10^{23} \times (7.956 \times 10^{-18})\\E' =4.78 \times 10^{6} \;\rm J[/tex]
Thus, the energy of one mole of photon is [tex]4.78 \times 10^{6} \;\rm J[/tex].
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