Force on a charge placed in electric field is given by
[tex] F = qE[/tex]
here [tex]q = -0.60 /mu C[/tex]
[tex]E = 1.2 * 10^6 N/c[/tex]
magnitude of force is given by
[tex]F = 1.2 * 10^6* 0.60 * 10^{-6}[/tex]
[tex]F = 0.72 N[/tex]
Direction of force is opposite to electric field direction as it is a negative charge
so direction is towards EAST