Question

Find the missing side round to the nearest tenth can someone plz help me

Answer 1

we are given

hypotenuse =x

angle =theta=43

adjacent=y

opposite =141

Calculation of x:

we can use sin formula

$sin(43)=\frac{141}{x}$

$x=\frac{141}{sin(43)}$

now, we can solve for x

$x=206.7$...........Answer

Calculation of y:

we can use tan formula

$tan(43)=\frac{141}{y}$

now, we can solve for y

$y=\frac{141}{tan(43)}$

we will get

$y=151.2$............Answer

Answer 2

From the given diagram, we are supposed to find the missing sides.

The given triangle is a right angled Triangle so one angle is 90 and another given angle is 43 degree

Now using the sine rule , we can write

$\frac{Sin43}{141}=\frac{Sin90}{x}\\\\\text{Simplify we get}\\\\x= \frac{Sin90}{sin43}*141\\\\\text{Now substitute the values and simplify we get}\\\\x= \frac{Sin90}{sin43}*141\\\\x= \frac{1}{sin43}*141, Sin90=1\\\\x=1.46628*141\approx 206.7$

Now we can write

$tan43=\frac{141}{y}\\ \\ y=\frac{141}{tan43}\\ \\ y=151.2$