Respuesta :
We can plug the given point in each equation and check if it satisfies it
1.
5x - 2y + 1 > 0
5(-2)-2(-1)+1>0
-10+2+1>0
-7>0 (false)
2.
-5x + 2y + 1 > 0
-5(-2) + 2(-1) + 1 > 0
10-2+1>0
9>0
so -5x + 2y + 1 > 0 satisfies the given point (-2,-1)
we are given point (-2, -1)
we can plug this point into inequality and check whether it holds true
(a)
[tex] 5x - 2y + 1 > 0 [/tex]
now, we can plug x=-2 and y=-1
[tex] 5*-2 - 2*-1 + 1 > 0 [/tex]
[tex] -10 +2 + 1 > 0 [/tex]
[tex] -7 > 0 [/tex]
this is not possible
point (-2,-1) does not satisfy inequality
(B)
[tex] -5x +2y + 1 > 0 [/tex]
now, we can plug x=-2 and y=-1
[tex] -5*-2 +2*-1 + 1 > 0 [/tex]
[tex] 10 -2 + 1 > 0 [/tex]
[tex] 9 > 0 [/tex]
this is true
point (-2,-1) does satisfy inequality
(C)
[tex] -2x +5y - 1 > 0 [/tex]
now, we can plug x=-2 and y=-1
[tex] -2*-2 +5*-1 - 1 > 0 [/tex]
[tex] 4 -5 - 1 > 0 [/tex]
[tex] -2 > 0 [/tex]
this is not true
point (-2,-1) does not satisfy inequality
(D)
[tex] 2x +5y - 1 > 0 [/tex]
now, we can plug x=-2 and y=-1
[tex] 2*-2 +5*-1 - 1 > 0 [/tex]
[tex] -4 -5 - 1 > 0 [/tex]
[tex] -10 > 0 [/tex]
this is not true
point (-2,-1) does not satisfy inequality
so,
option-B.........Answer