Answer:-
0.3 moles
Explanation:-
According to the question,
Volume of nitrogen gas V = 6.8 litres.
Pressure of nitrogen gas P = 100 kPa.
Temperature of nitrogen gas T = 273 K.
We know the value of universal gas constant R = 8.314 litres kPa K−1 mol−1
Using the relation
PV = nRT
We have Number of moles of nitrogen gas n = P V / RT
= 100 kPa x 6.8 litres / ( 8.314 litres kPa K−1 mol−1 x 273 K)
= 0.3 mol
Thus there are 0.3 moles of nitrogen gas in 6.8 liters at standard temperature and pressure (273 K and 100 kPa)
