Respuesta :
The order of the start of the proof seems fine; we're to choose the next steps I guess.
segment UV is parallel to segment WZ Given
Points S, Q, R, and T all lie on the same line. Given
m∠SQT = 180° Definition of a Straight Angle
m∠SQV + m∠VQT = m∠SQT Angle Addition Postulate
m∠SQV + m∠VQT = 180° Substitution Property of Equality
That's all valid up to here. It seems to me sort of the hard way to get to linear supplements but here we are.
ZRS is mentioned in the rest of the lines; let's find the one that comes first.
III m∠VQT + m∠ZRS = 180° Same-Side Interior Angles Theorem
Now we have two things equal to 180 degrees, so they're equal to each other.
II m∠SQV + m∠VQT = m∠VQT + m∠ZRS Substitution Property of Equality
Now comes
I m∠SQV + m∠VQT − m∠VQT = m∠VQT + m∠ZRS − m∠VQT
m∠SQV = m∠ZRS Subtraction Property of Equality
And we conclude,
∠SQV ≅ ∠ZRS Definition of Congruency
The corresponding angles formed by two parallel lines, having the same transversal are congruent
The correct order of the statements are;
- III m∠VQT + m∠ZRS = 180°
- II m∠SQV + m∠VQT = m∠VQT + m∠ZRS
- I m∠SQV + m∠VQT - m∠VQT = m∠VQT m∠ZRS - m∠VQT
The reason the above statements are in the correct order is as follows:
The two column proof is presented as follows;
Statements [tex]{}[/tex] Reason
Segments UV is parallel to segment WZ [tex]{}[/tex] Given
Points S, Q, R, and T all lie on the same line [tex]{}[/tex] Given
m∠SQT = 180° [tex]{}[/tex] Definition of a straight angle
m∠SQV + m∠VQT = m∠SQT [tex]{}[/tex] Angle Addition Postulate
m∠SQV + m∠VQT = 180° [tex]{}[/tex] Substitution Property of Equality
III m∠VQT + m∠ZRS = 180° [tex]{}[/tex] Same-side interior angle theorem
II m∠SQV + m∠VQT = m∠VQT + m∠ZRS [tex]{}[/tex] Substitution Property of Equality
I m∠SQV + m∠VQT - m∠VQT = m∠VQT
+ m∠ZRS - m∠VQT [tex]{}[/tex] Subtraction Property of Equality
m∠SQV = m∠ZRS [tex]{}[/tex]
m∠SQV ≅ m∠ZRS [tex]{}[/tex] Definition of Congruency
Therefore, the correct order is as follows;
First
- III m∠VQT + m∠ZRS = 180°; Given that m∠VQT and m∠ZRS are same side interior angles
Second
- II m∠SQV + m∠VQT = m∠VQT + m∠ZRS; [tex]{}[/tex] By Substitution Property of Equality given that both (m∠SQV + m∠VQT), (m∠VQT + m∠ZRS) are equal to 180°
Third
- I m∠SQV + m∠VQT - m∠VQT = m∠VQT m∠ZRS - m∠VQT; The same value - m∠VQT is subtracted from both sides of the equation in Step II, therefore, both sides of the equation remains equal
Learn more about the angles formed by two parallel lines here:
https://brainly.com/question/13702600