Respuesta :
In the beginning number of students are 18 .
And each year they increase by 2, that is
18 , 18+2, 18+2+2 , 18+2+2+2,.......
So the series is in arthmetic progression, where first term is 18 and common difference is 2 .
To find the 25th term, we will use the following formula
a(n) = a + (n-1)d = 18+(25-1)*2 = 18 + 48 = 66
And to find the sum , we will use the following formula
S = 0.5 n (a+l), where l is the last term which is 66.
S =0.5*25(18+66) = 1050
Correct option is the third option .