Question

factor, show all steps. x2 – 16x + 64 = 0

Answer 1

$x^2-16x+64=0$

Method 1.

Use $(a-b)^2=a^2-2ab+b^2$

$x^2-2\cdot x\cdot8+8^2=0\\\\(x-8)^2=0\\\\(x-8)(x-8)=0$

Method 2.

$x^2-8x-8x+64=0\\\\x(x-8)-8(x-8)=0\\\\(x-8)(x-8)=0$

The solution to this equation is the number 8

Answer 2

Hey,here is the answer to ur question....
x^2-16x+64=0
Sum=-16
Product=64
So,
x^2-8x-8x+64
x(x-8) -8(x-8)
(x-8)(x-8)
=>(x-8)^2
Hope this helps u........